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5m^2-4m-57=0
a = 5; b = -4; c = -57;
Δ = b2-4ac
Δ = -42-4·5·(-57)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-34}{2*5}=\frac{-30}{10} =-3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+34}{2*5}=\frac{38}{10} =3+4/5 $
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